Consider two blocks of mass m_1 = 5 , kg and | vedclass

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(C) For the $5 \, kg$ block,the maximum static friction force is $f_{s1} = \mu m_1 g = 0.2 	imes 5 	imes 10 = 10 \, N$.For the $10 \, kg$ block,the

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$30$

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(C) For the $5 \, kg$ block,the maximum static friction force is $f_{s1} = \mu m_1 g = 0.2 	imes 5 	imes 10 = 10 \, N$.For the $10 \, kg$ block,the maximum static friction force is $f_{s2} = \mu m_2 g = 0.2 	imes 10 	imes 10 = 20 \, N$.For the system to remain at rest,the applied force $F$ must be balanced by the total maximum static friction of the system.However,the $5 \, kg$ block will only move if the force transmitted to it exceeds $10 \, N$. Since the force $F$ is applied to the $10 \, kg$ block,the entire system will start moving when $F$ exceeds the total friction $f_{s1} + f_{s2} = 10 + 20 = 30 \, N$.Thus,the maximum force $F$ that will not cause motion of any block is $30 \, N$.

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